© 2004 Rasmus ehf |
Percentages and interest |
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Lesson 6
Interest over time
Calculating the compounding period
Interest:
If you keep money in a bank, the bank pays you for the use of the money. The money they pay is interest. Interest is calculated as a percent of the bank balance.
If you have 1500 euros in a bank account for a whole year and the interest rate is 12% pa. (pa. means per annum = per year), you can find the amount of interest by calculating the the percentage.
interest rate (% per year) × principal = interest
0.12 × 1500 euros = 180
The amount of interest earned for the year is 180 euros.
Interest over time:
If you have 1500 euros in a bank account for half a year or 6 months, the interest earned is:
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is the interest for half a year. |
This can be calculated all at once by including the time factor (t) in the formula.
interest rate × principal × time = interest
0.12 × 1500 euros ×0.5 = 90 euros | is the interest for half a year. |
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half a year |
If the amount is kept in a bank account for 3 months, the interest is calculated as follows:
interest rate × principal × time = interest (rPt = I)
0.12 × 1500 euros × 0.25 = 45 euros
The interest earned for 3 months is 45 euros. Top of page!
A month is calculated as 30 days and 12 months in a year make 360 days.
If you deposit 1500 euros in a bank account on August 26 at 12% interest pa., how much money will there be in the account on Nov. 8?
First calculate the number of days in the interest compounding period: | ||
period | days | |
August (30-26) | 4 | |
Sept. | 30 | |
Okt. | 30 | |
Nov. | 8 | |
Total: | 72 |
72 days out of 360 are 0.2 of a year. The interest earned is:
0.12 × 1500 euros × 0.2 = 36 euros.
You will have the principal of 1500 euros plus interest 36 = 1536 euros.
Let's say that you have earned 45 euros in interest on a principal of 1500 euros over the last 3 months. How can you find out what the annual interest rate is?
Note: three months is one fourth of a year (3/12 = 0.25 ).
interest rate × principal × time = interest | Use the formula for calculating interest. |
p × 1500 euros × 0.25 = 375 euros | Put in the known values. |
p × 375 euros = 45 euros | Simplify by multiplying the principal by time |
p = 45/375 = 0.12 = 12/100 = 12% | Divide by the factor of r and convert the decimal into a percentage. |
r · P · t = interest r = interest rate, P = principal, t = time
Calculating the compounding period by using the interest formula
The interest earned on a principal of 18000 euros at 12% pa. was 72 euros. How long (compounding period) was the money kept in the bank account?
interest rate × principal × time = interest | Use the formula for calculating interest. |
0.12 × 18000 × t = v | Put in the values for the interest rate and the principal. |
18000 × t = 72 | Simplify by multiplying the principal by the interest rate. |
t = 72/18000 = 0.4 | Divide by the factor of t . |
0.4 = 4/10 and 360 × 4/100 = 144 days | Multiply the number of days per year by the result to get the number of days in the compounding period. |
Principal in an account has earned interest for 288 days at 12 % pa. The amount in the bank account is now 1644 euros. How do we find the principal (the amount of money put in the account)?
Note: 288 days of 360 is 0.8 of a year.
interest rate × principal × time = interest | Use the formula for calculating interest. |
0.12 × whole × 0.8 = interest | Put in the values for the interest rate and the time. |
p + 0.12 × whole × 0.8 = interests + p | Add the principal P to both sides of the equation. |
p + 0.096p = 1644 | Multiply 0.12 and 0.8 and put in the value for the principal plus interest. |
1.096p = 1644 | 1P + 0.096P = 1.096P |
p = 1644/1.096 = 1500 euros | Divide by the factor of P to find the principal. |
The principal was 1500 euros and it earned interest for 288 days.
Interest compounded over years
Find 12% interest on 1500 euros for one year.
0.12 × 1500 euros = 180 euros | 1500 euros + 180 euros = 1680 euros |
1500 euros × 1.12 = 1680 euros | 1680 euros is 112% of 1500. |
Compounded interest can be calculated in one operation by adding 1 to the interest percent rate (1.12) and multiplying. The result is the principal plus the interest earned for one year. To find the new principal for additional years, continue to multiply by 1.12.
1 year | 1500 × 1.12 = 1680 euros | 1500 euros × 1.12 = 1680 euros |
2 years | 1680 × 1.12 = 1881.6 euros | 1500 euros × 1.12 × 1.12 = 1881.6 |
3 years | 1881.6 × 1.12 = 2107.4 euros | 1500 euros × 1.12 × 1.12 × 1.12 = 2107.4 euros |
Here we see the compounded principal after 3 and 5 years at 12% interest:
Compounded principal after 3 years | 1500 euros × 1.123 = 2107.4 euros | |
Compounded principal after 5 years | 1500 euros × 1.125 = 2643.5 euros |
The principal plus interest after 5 years (compounded interest) is:
The formula for
compounded principal is
where:
H = compounded principal |
h = initial principal |
p = interest rate |
x = number of years |
Try Quiz 6 in Percentages and interest.